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Wednesday, June 12, 2013

A Beer's Law Study

Nathan Bahn Beers Law ask Lab Introduction: In this lab, we go for a spectrometer to keep the transmittance of unaffixed at a certain undulate length. We experimented to divulge if the breakwaterarity of a answer of purpose changes the transmittance of light and the absorbance of that light by the solution. By observing the percent transmittance and the amount of light absorbed, we pouf calculate the amount of colouration absorbing components in the solution. by this process is how we are able-bodied to discover the amount of atomic number 29 in the solution. Experimental Procedure: 250 mL of the slovenly person solution was do by creating 100 mL of the solution, reacting CuO with HNO3, and then diluting to the determine of 250 mL. use this stock solution, different concentrations were do and placed in the sprectrometer for observation. The absorbances and transmittances were preserve for use when identifying the amount of the color-absorbing copper ions later. A graph was plan of Absorbance v. groinar(a) Concentration easily see the results of the experiment. Pre-Lab Questions: 1. Absorbance = - pound10T = 2- enter10 (%T) a) 2 lumber (89.95) = .0460f) 2 Log (28.18) = .5501 b) 2 Log (80.91) = .0920g) 2 Log (20.51) = .6880 c) 2 Log (59.02) = .2290h) 2 Log (17.38) = .7600 d) 2 Log (47.75) = .3210i) 2 Log (14.45) = .8401 e) 2 Log (34.83) = .
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4580 2. Molar Concentration 1.213 g Cu (1 mol Cu/ 63.546 g Cu) (1 mol [Cu (H2O6)2+]/ 1 mol Cu) (1/ .100 L) = .191 M [Cu (H2O6)2+] a) M2 = (M1V1)/V2M2 = (.191 M [Cu (H2O6)2+])( 1.0 mL)/ (50.0 mL) = .0038 M b) (.191 M [Cu (H2O6)2+]) (2.0 mL)/ (50.0 mL) = .0076 M c) (.191 M [Cu (H2O6)2+]) (5.0 mL)/ (50.0 mL) = .0191 M d) (.191 M [Cu (H2O6)2+]) (7.0 mL)/ (50.0 mL) = .0267 M e) (.191 M [Cu (H2O6)2+]) (10.0 mL)/ (50.0 mL) = .0382 M f) (.191 M [Cu (H2O6)2+]) (12.0 mL)/ (50.0 mL) = .0458 M g) (.191 M [Cu (H2O6)2+]) (15.0 mL)/ (50.0 mL) = .0573 M h) (.191 M [Cu (H2O6)2+]) (17.0 mL)/ (50.0 mL) = .0649 M i) (.191 M [Cu...If you want to astonish a full essay, lay out it on our website: Orderessay

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